x_calculation_step vs convolution_step

rowlesmr

In my specific case, I've got constant step-width data, but in general:

Is there any difference between saying

x_calculation_step = Yobs_dx_at(Xo);
convolution_step = n;

x_calculation_step = Yobs_dx_at(Xo)/n;
convolution_step = 1;

for any number n > 1?

alancoelho

There is a difference.

The x_calculation_step applies to all equations involving Ycalc.

convolution_step changes the peak_calculation_step which affects convolutions only.

convolution_step also divides the peak_calculation_step such that the original data points coincide with the new data points.

The above means that using convolution_step is a lot quicker than using changing x_calculation_step; additionally it is more accurate if x_calculation_step does not have the new data points coinciding with the original data points.

rowlesmr

Thanks

I'll have to experiment a bit with my low-res quant data.